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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3. int getCount(int n,int k,vector<int>arr){
  4. 	int i=0;
  5. 	int count=0;
  6. 	for(int j=0;j<n;j++){
  7. 		int diff=arr[j]-arr[i];
  8. 		while(diff>k){
  9. 			i++;
  10. 			diff=arr[j]-arr[i];
  11. 		}
  12. 		count=count+(j-i+1);
  13. 	}
  14. 	return (count-n);
  15.  
  16. }
  17.  
  18. int main() {
  19. 	// your code goes here
  20. 	int n;
  21. 	cin>>n;
  22. 	vector<int>arr(n,0);
  23. 	for(int i=0;i<n;i++){
  24. 		cin>>arr[i];
  25. 	}
  26. 	int k;
  27. 	cin>>k;
  28. 	sort(arr.begin(),arr.end()); //need to sort for j>i
  29.  
  30. 	cout<<"Count of pairs with difference<=k:"<<getCount(n,k,arr);
  31. 	return 0;
  32. }
Success #stdin #stdout 0.01s 5324KB
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Count of pairs with difference<=k:5
https://ideone.com/zJlHXX
language:
C++ (gcc 8.3)
created:
7 days ago
visibility:
public

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