#include <stdio.h>
// a[n] = 2a[n-1] + a[n-2], a[1]=2, a[2]=3(再帰なし版)
int main(void) {
int n = 4;
int a, b = 3, c = 2;
for(int i = 3; i <= n; i++){
a = 2*b + c;
c = b; // 先に c に旧 b の値を入れる
b = a; // その後 b に新しい a を入れる
}
return 0;
}
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