#include <stdio.h>
//a{n} = -6a{n-1} -9a{n-2}, a{1}=1, a{2}=2(再帰あり版)
int c=0;
int rec(int n){
if(n==1){
return 1+c++;
}
else if(n==2){
return 2+c++;
}
else{
return -6*rec(n-1)-9*rec(n-2)+c++;
}
}
int main(void) {
int n = 5;
printf("数列a%dの値は%d\nこのときrecの呼び出し回数は%d", n
, rec
(n
),c
); return 0;
}
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