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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4. 	if (n <= 1){
  5. 		return 1;
  6. 	}
  7. 	else{
  8. 		return n+rec(n-2);
  9. 	}
  10. }
  11. int main(void) {
  12.     int n = 10;
  13. 	if(n%2==1){
  14. 	    printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  15. 	}
  16. 	else{
  17. 		printf("%d以下の正の偶数の和は%d\n", n, rec(n));
  18. 	}
  19. 	return 0;
  20. }
Success #stdin #stdout 0s 5320KB
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10以下の正の偶数の和は31
https://ideone.com/rEV25k
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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