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  1. #include <stdio.h>
  2. //a{n}=-6a{n-1}-9a{n-2},a{1}=1,a{2}=2(再帰なし版)
  3.  
  4. int main(void){
  5. 	int n=4;
  6. 	int a,b=2,c=1; 
  7. 	for(int i=3;i<=n;i++){
  8. 		a=-6*b-9*c;
  9. 		c=b;
  10. 		b=a;
  11. 	}
  12. 	printf("数列a%dの値は%d\n", n, a);
  13. 	return 0;
  14. }
  15.  
  16.  
Success #stdin #stdout 0s 5304KB
comments (?)
stdin 
Standard input is empty
stdout 
数列a4の値は108
https://ideone.com/nLfBC9
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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