#include <iostream>
using namespace std;
int main() {
// your code goes here
int b[]={5,6,4,3,6};
int n=sizeof(b)/sizeof(b[0]);
int k=3;
int count=0;
for(int i=0;i<n;i++){
for(int j=i+1;j<n;j++){
if(abs(b[i]-b[j])==k){
count++;
}
}
}
cout<<count;
return 0;
}
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