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  1. #include <stdio.h>
  2. //a{n} = -6a{n-1} -9a{n-2}, a{1}=1, a{2}=2(再帰あり版)
  3. int rec(int n){
  4. 	if(n==1) return 1;
  5. 	else if(n==2) return 2;
  6. 	else return -6*rec(n-1)-9*rec(n-2);
  7. }
  8.  
  9. int main(void) {
  10.     int n = 2;
  11.     printf("数列a%dの値は%d\n", n, rec(n));
  12. 	return 0;
  13. }
  14.  
  15.  
Success #stdin #stdout 0s 5308KB
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Standard input is empty
stdout
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数列a2の値は2
https://ideone.com/ex5czv
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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