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  1. #include <stdio.h>
  2. //a{n+1} = -2a{n} + 4, a{0}=2(再帰なし版)
  3. int main(void) {
  4.     int i,n;
  5.     scanf("%d",&n);
  6.     int an=2;
  7. for(i=0;i<n;i++){
  8. 	an=-2*an+4;
  9. }
  10.     printf("数列a%dの値は%d\n", n, an);
  11.  
  12. 	return 0;
  13. }
  14.  
  15.  
Success #stdin #stdout 0s 5308KB
comments (?)
stdin 
4
stdout 
数列a4の値は12
https://ideone.com/asqSkq
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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