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  1. #include <stdio.h>
  2.  
  3. // 正の奇数nを引数とし、n以下の正の奇数の和を求める関数
  4. int rec(int n){
  5.     if (n == 1){
  6.         return 1;          // ★ 1だけのときは 1
  7.     }
  8.     else{
  9.         return rec(n - 2) + n;   // ★ 1つ前の奇数までの和 + n
  10.     }
  11. }
  12.  
  13. int main(void) {
  14.     int n = 11;
  15.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  16.     return 0;
  17. }
  18.  
Success #stdin #stdout 0.01s 5320KB
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11以下の正の奇数の和は36
https://ideone.com/WtVLmA
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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