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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4. 	if(n==1){
  5. 		return 1;
  6. 	}else if(n==0){
  7. 		return 0;
  8. 	}else {
  9. 		return n+rec(n-2);
  10. 	}
  11. 	}
  12.  
  13. int main(void) {
  14.     int n = 18;
  15.     if(n%2==0){
  16.      printf("%d以下の正の偶数の和は%d\n", n, rec(n));
  17.     }else{
  18.     	 printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  19.     }
  20. 	return 0;
  21. }
Success #stdin #stdout 0s 5320KB
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18以下の正の偶数の和は90
https://ideone.com/LAa2bx
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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