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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4.  int i,j;
  5. for(i=0;s[i+1]!='\0';i++);
  6. while(j<=i){
  7.   if(s[j++]!=s[i--]){
  8.   return 0;
  9. }
  10.   return 1;
  11. }
  12.  //回文になっているとき１を返す
  13.  //回文になっていないとき０を返す
  14. }
  15.  
  16. //メイン関数は書き換えなくてよいです
  17. int main(){
  18.     char s[100];
  19.     scanf("%s",s);
  20.     printf("%s -> %d\n",s,isPalindrome(s));
  21.     return 0;
  22. }
Success #stdin #stdout 0.01s 5288KB
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https://ideone.com/Esti5P
language:
C (gcc 8.3)
created:
8 days ago
visibility:
public

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