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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	int n;
  5.  
  6. 	for(int i0=0;s[i0]!='\0';i0++){
  7. 		n=i0;
  8. 	}
  9.  
  10. 	for(int i1=0;i1<n-i1&&i1!=n-i1;i1++){
  11. 		if(s[i1]!=s[n-i1]){
  12. 			return 0;
  13. 		}
  14. 	}
  15. 	return 1;
  16. }
  17.  
  18. int main(){
  19.     char s[100];
  20.     scanf("%s",s);
  21.     printf("%s -> %d\n",s,isPalindrome(s));
  22.     return 0;
  23. }
  24.  
Success #stdin #stdout 0.01s 5284KB
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https://ideone.com/DAfeh2
language:
C (gcc 8.3)
created:
8 days ago
visibility:
public

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