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  1. #include <stdio.h>
  2. //a{n+1}=-2a{n}+4,a{0}=2(再帰なし版)
  3. int main(void){
  4.     int n,an=2;
  5. 	scanf("%d",&n);
  6. 	for(int i=0;i<n;i++){
  7. 		an=-2*an+4;
  8. 	}
  9.     printf("数列a%dの値は%d\n",n,an);
  10.  
  11. 	return 0;
  12. }
  13.  
Success #stdin #stdout 0.01s 5284KB
comments (?)
stdin 
Standard input is empty
stdout 
数列a0の値は2
https://ideone.com/70PtUd
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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