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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n == 0){
  5.         return 0;
  6.     }
  7.     else if(n==1){
  8.     	return 1;
  9.     }
  10.     else{
  11.         return n+rec(n-2);
  12.     }
  13. }
  14. int main(void) {
  15.     int n = 11;
  16.     if(n%2==1){
  17.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  18.     }
  19.     else {
  20.     	printf("%d以下の正の偶数の和は%d\n",n,rec(n));
  21.     }
  22. 	return 0;
  23. }
Success #stdin #stdout 0.01s 5288KB
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11以下の正の奇数の和は36
https://ideone.com/6rcNar
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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