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  1. #include <iostream>
  2. using namespace std;
  3. typedef long long ll;
  4. int main(){
  5.     int t, n, m;
  6.     cin >> t;
  7.     while (t--){
  8.         cin >> n >> m;
  9.         if (m >= 2 * n) cout << "No\n";
  10.         else{
  11.             cout << "Yes\n";
  12.             for (int i = 0; i < 2 * n; ++i){
  13.                 for (int j = 0; j < m; ++j) cout << (j + i) / 2  % n + 1 << " ";
  14.                 cout << "\n";
  15.             }
  16.         }
  17. 	}
  18. }
Success #stdin #stdout 0.01s 5268KB
comments (?)
stdin
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1
4 6
stdout
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Yes
1 1 2 2 3 3 
1 2 2 3 3 4 
2 2 3 3 4 4 
2 3 3 4 4 1 
3 3 4 4 1 1 
3 4 4 1 1 2 
4 4 1 1 2 2 
4 1 1 2 2 3
https://ideone.com/3MeMLl
language:
C++ (gcc 8.3)
created:
9 days ago
visibility:
public

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