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  1. import math
  2.  
  3. K = 4.201
  4. L = 3
  5.  
  6. try:
  7.     x = float(input("Enter value for x: "))
  8.  
  9.     if x < 0:
  10.         raise ValueError("ERROR: The negative value in square root!")
  11.  
  12.     a_calc_part = K * math.sqrt(x) + 2 - (1 / L) * (math.exp(2) - math.exp(-2))
  13.     if a_calc_part < 0:
  14.         raise ValueError("ERROR: The negative value in square root for 'a'!")
  15.  
  16.     a = math.sqrt(a_calc_part)
  17.     b = math.sin(0.5 * math.atan(-0.25) * math.log(5))
  18.  
  19.     if a > 2 * b:
  20.         y = math.sqrt(3 * a - 5 * b)
  21.     elif a == 2 * b:
  22.         y = a
  23.     else:
  24.         y_calc_part = 3 * a + 5 * b
  25.         if y_calc_part < 0:
  26.             raise ValueError("ERROR: The negative value in square root for 'y'!")
  27.         y = math.sqrt(y_calc_part)
  28.  
  29.     print("Result y = {:.4f}".format(y))
  30.  
  31. except ValueError as e:
  32.     print(e)
  33. except ZeroDivisionError:
  34.     print("ERROR: Division by zero occurred!")
  35. except Exception:
  36.     print("ERROR: An unknown error occurred!")
Success #stdin #stdout 0.02s 7780KB
comments (?)
stdin 
3.14
stdout 
Enter value for x: Result y = 3.1935
https://ideone.com/2pnjiv
language:
Python (cpython 2.7.16)
created:
1 day ago
visibility:
public

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