#include <stdio.h>
// a{n} = 2a{n-1} + a{n-2}, a{1}=2, a{2}=3
int main(void) {
int n = 4;
int a1 = 2, a2 = 3, a3;
for (int i = 3; i <= n; i++) {
a3 = 2 * a2 + a1;
a1 = a2;
a2 = a3;
}
printf("数列a%dの値は%d\n", n
, a3
); return 0;
}
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